cart on a ramp
Purpose:
-A motion detector
-A metal track
-a cart
-a block to stop the cart's motion
-feet to angle the track
-LabQuest device
Procedure:
1. Prepare the track and Motion Detector for data collection.
a. Attach the Motion Detector Bracket to the track.
b. Attach the Motion Detector to the Motion Detector Bracket.
c. Adjust the position of the Motion Detector Bracket so the Motion Detector is 0.15m from the end of the track.
d. Set the switch on the Motion Detector to the Track position.
2. Connect the Motion Detector to DIG 1 of LabQuest and choose New from the File menu.
3. Place the cart on the track near the bottom end stop. If your cart has a plunger, face the plunger away from the Motion Detector. Start data collection. You will notice a clicking sound from the Motion Detector. Wait about a second, the briefly push the cart up the ramp, letting it roll freely up nearly to the top, and then back down. Catch the cart as it nears the end stop.
4. Examine the position vs. time graph. Repeat step 3 if your position vs. time graph does not show an area of smoothly changing distance. Check with your instructor if you are not sure whether you need to repeat data collection.
Data and Analysis:
- Collect distance, velocity, and acceleration data as a cart rolls up and down a ramp.
- Analyze the position vs. time, velocity vs. time, and acceleration vs. time graphs.
- Determine the best fit equations for the distance vs. time and velocity vs. time graphs.
- Determine the mean acceleration from the acceleration vs. time graph.
-A motion detector
-A metal track
-a cart
-a block to stop the cart's motion
-feet to angle the track
-LabQuest device
Procedure:
1. Prepare the track and Motion Detector for data collection.
a. Attach the Motion Detector Bracket to the track.
b. Attach the Motion Detector to the Motion Detector Bracket.
c. Adjust the position of the Motion Detector Bracket so the Motion Detector is 0.15m from the end of the track.
d. Set the switch on the Motion Detector to the Track position.
2. Connect the Motion Detector to DIG 1 of LabQuest and choose New from the File menu.
3. Place the cart on the track near the bottom end stop. If your cart has a plunger, face the plunger away from the Motion Detector. Start data collection. You will notice a clicking sound from the Motion Detector. Wait about a second, the briefly push the cart up the ramp, letting it roll freely up nearly to the top, and then back down. Catch the cart as it nears the end stop.
4. Examine the position vs. time graph. Repeat step 3 if your position vs. time graph does not show an area of smoothly changing distance. Check with your instructor if you are not sure whether you need to repeat data collection.
Data and Analysis:
Conclusion: During the making of the graphs, we learned what it looks like for an object to be in motion when it comes to Position vs. Time, Velocity vs. Time, and Acceleration vs. Time. The first point marks the beginning of the motion, and the last point marks the end. The keys and colors helps tell what each arrow means. The Position vs. Time graph had more of a U shape and a lot of movement. The Velocity vs. Time had a check- mark shape and started out going down but then went up. The Acceleration vs. Time graph started out and ended with a lot of motion, but in the middle in was close to being constant.
1. The slope of the velocity graph is about the rate of acceleration.
2. The velocity of the cart at the top of its motion was about 0.555 m/s.
3. The cart's acceleration at the top of its motion was about 0.373 m/s².
4. Yes, the cart's acceleration is constant during the free-rolling segment.
5. Yes, I agree with #1 and #3 on my preliminary question answers, but I do not agree with #2. #2 should be a straight diagonal line.
6. The slope of my equation (0.32204x - 0.70153) is 0.32204, which tells you how much the velocity goes up per second, and the y-intercept (0.70153) tells you the original amount.
7. The position would have a curved line, but the curve would only go in one direction, The velocity would only go in one direction, on the positive side, and stop. The acceleration would be a straight line at 9.8 m/s²
1. The slope of the velocity graph is about the rate of acceleration.
2. The velocity of the cart at the top of its motion was about 0.555 m/s.
3. The cart's acceleration at the top of its motion was about 0.373 m/s².
4. Yes, the cart's acceleration is constant during the free-rolling segment.
5. Yes, I agree with #1 and #3 on my preliminary question answers, but I do not agree with #2. #2 should be a straight diagonal line.
6. The slope of my equation (0.32204x - 0.70153) is 0.32204, which tells you how much the velocity goes up per second, and the y-intercept (0.70153) tells you the original amount.
7. The position would have a curved line, but the curve would only go in one direction, The velocity would only go in one direction, on the positive side, and stop. The acceleration would be a straight line at 9.8 m/s²